20c^2-13c-15=0

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Solution for 20c^2-13c-15=0 equation:


Simplifying
20c2 + -13c + -15 = 0

Reorder the terms:
-15 + -13c + 20c2 = 0

Solving
-15 + -13c + 20c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -5c)(5 + -4c) = 0

Subproblem 1

Set the factor '(-3 + -5c)' equal to zero and attempt to solve: Simplifying -3 + -5c = 0 Solving -3 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -5c = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -5c = 0 + 3 -5c = 0 + 3 Combine like terms: 0 + 3 = 3 -5c = 3 Divide each side by '-5'. c = -0.6 Simplifying c = -0.6

Subproblem 2

Set the factor '(5 + -4c)' equal to zero and attempt to solve: Simplifying 5 + -4c = 0 Solving 5 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -4c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -4c = 0 + -5 -4c = 0 + -5 Combine like terms: 0 + -5 = -5 -4c = -5 Divide each side by '-4'. c = 1.25 Simplifying c = 1.25

Solution

c = {-0.6, 1.25}

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